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Common Resistor values (bands 1-3):
Black 0 Brown 1 Red 2 Orange 3 Yellow 4 Green 5 Blue 6 Violet 7 Gray 8 White 9 gold .1 silver .01
Tolerance (band 4):
no band 20% silver 10% gold 5%
Common Resistor color bands and what each position means - Common resistors (draw):
Precision Resistor values (bands 1-4) *basically 1 more band:
Black 0 Brown 1 Red 2 Orange 3 Yellow 4 Green 5 Blue 6 Violet 7 Gray 8 White 9 gold .1 silver .01
Tolerance (band 5):
brown 1% red 2% orange 3% silver 10% gold 5%
Precision Resistor color bands and what each position means - Precision Resistors:
Series circuit 3 rules for series, about: 1. Current: same everywhere based on total resistance 2. Resistance: just adds each resistor 3. Volts: drop after every resistor
Parallel circuit 3 rules for parallel, about: 1. Current: every new bridge adds current 2. Resistance: Resistor of one branch/Number of branch (product/Sum) 3. Volts: same voltage in every bridge
The 3 rules for a Series Circuit: 1. Current: Same everywhere based on resistance 2. To get total Resistance: just add each resistance (Rtot=R1+R2+R3) 3. Volts: Drops after every resistor (E=IxR)
The 3 rules for Parallel Circuit: 1. Current: Every new bridge adds current (Itot=I1+I2+I3) 2. To get total Resistance: a) Resistance of one branch/# of branch (Rtot = R1/# of branch) b) If different then product/Sum Ω (Rtot = R1 x R2/R1+R2) *Total resistance is always “less” than the one of smallest branch 3. Volts: Same voltage in every bridge
What is the total resistance of this series circuit below? 20 Ω
; E = I x R, 0.5A x 10Ω = 5V, thus 5V drop
Use the Voltage Division formula for the same circuit. Don’t have to figure Current. Show your work. ; E = I x R; E1 + E2 = 10V; IR1 + IR2 = 10V
What is the total resistance for this parallel circuit below? 1.335 Ω
; Itot = I1 + I2 ; I = E/R, so Itot = E/R1 + E/R2 ; 10/2 + 10/4 = 5A + 2.5A ; Thus, total I = 7.5 A (= 10V/1.335 Ω)
What is the Total current for the above parallel circuit? 7.5 A
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